Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is (g=10m/`s^(2)`

Options

A. `2pim//s`
B. `pim//s`
C. `(1)/(pi)m//s`
D. `(1)/(2pi)m//s`

Answer

D

Explanation

Amplitude=elongation in equilibrum position.
`A=(mg)/(k)` `V_(max)=Aomega=Aomega=(mg)/(K)omega=(g)/(omega)=(g)/(2pif)=(g)/(2pixx10)=(1)(2pi)m//s(omega=sqrt((K)/(M)))`