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A spring of force constant k is cut into...

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

A

`(2//3)k`

B

`(3//2)k`

C

3k

D

6k

Text Solution

Verified by Experts

The correct Answer is:
B
`k_(1)I_(1)=k_(2)I_(2)=k[I_(1)+I_(2)]Rightarrow K_(1)=(k[I_(1)+I_(2)])/(I_(1))=k(3)/(2) Rightarrowk_(1)=(3)/(2)k`
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