Time period of a simple pendulum of length L is `T_(1)` and time period of a uniform rod of the same length L pivoted about an end and oscillating in a vertical plane is `T_(2)`. Amplitude of osciallations in both the cases is small. Then `T_(1)/T_(2)` is

Options

A. `sqrt((4)/(3))`
B. 1
C. `sqrt((3)/(2))`
D. `sqrt((1)/(3))`

Answer

C

Explanation

`T_(1)=2pisqrt((L)/(g))`, `T_(2)=2pisqrt((I)/(mgxx(L)/(2)))(I+mL^(2)I3) Rightarrow (T_(1))/(T_(2))`