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Figure shows the circular motion of a pa...

Figure shows the circular motion of a particle. The radius of the circle, the period, same of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector the rotating particle P is

A

`x(t)= B cos((2pit)/(30))`

B

`x(t)= B sin((pit)/(15))`

C

`x(t)= B sin((pit)/(15) + (pi)/(2))`

D

`x(t)= B sin((pit)/(15) + (pi)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

`omega=(2pi)/(T)=(2pi)/(30)=(pi)/(15)rad//s`.
x projection of P=`Bsin(( pi)/(15)t)`.
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