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A thin bar of mass M and length L is fre...

A thin bar of mass `M` and length `L` is free to rotate about a fixed horizontal axis through a point at its end. The bar is brought to a horizontal position and then released. The axis is perpendicular to the rod. The angular velocity when it reaches the lowest point is

A

`omega`

B

`2omega`

C

`omega//2`

D

`4omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`omega=sqrt((mgd)/(I))`, `2mgd=(1)/(2)//Omega^(2)`
`Omega=sqrt((4mgd)/(I))=2omega`
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