Force acting on a particle is `F=-8x` in S.H.M. The amplitude of oscillation is 2 (in m) and mass of the particle is 0.5 kg. The total mechanical energy of the particle is 20 J. Find the potential energy of the particle in mean position (in J).

Answer

4

Explanation

K=8N//m Since, F=-8x
`A=F//m=(-8x)/(0.5)=-16x`
`omega=(16)^((1)/(2))=4rad//sec`.
`(1)/(2)KA^(2)=(1)/(2)(8)(2)^(2)=16J`
Potential energy at the mean position =`E-(1)/(2)KA^(2)=20-16=4J`