A constant force produces maximum velocity V on the block connected to the spring of force constant K as shown in the figure. When the force constant of spring becomes 4K, the maximum velocity of the block is

Answer

C

Explanation

`A=(F)/(k)`,`omega=sqrt((k)/(m))`,`V=Aomega`
`A'=(F)/(4k)`,`omega'=sqrt((4k)/(m))`, `V'=A'omega'=(F)/(4k)2sqrt((k)/(m))=(V)/(2)`