In the Column I, a system is described in each option and corresponding time period is given in the column – II, Suitably match them.

Answer

A-P;B-Q;C-P;D-S

Explanation

(A) In frame of lift, effective acceleration due to gravity is `g+(g)/(2)=(3g)/(2)` downwards ` therefore T=2pisqrt((2I)/(3g))`
(B) `KI=mg therefore=(k)/(m)=(g)/(L)`
Constant acceleration of lift has no effect in time period of oscillation.
`therefore T=2pisqrt((m)/(k))=2pisqrt((I)/(g))`
(C) `T=2pisqrt((I)/(mgd))=2pisqrt((((mI)^(2))/(3))/(mg(I)/(2)))=2pisqrt((2I)/(3g))`
`T=2pisqrt((m)/(pAg))=2pisqrt((p//2AI)/(pAg))=2pisqrt((I)/(2g))`