The angular frequency of a spring block system is `omega_(0)`. This system is suspended from the ceiling of an elevator moving downwards with a constant speed `v_(0)`. The block is at rest relative to the elevator. Lift is suddenly stopped. Assuming the downward as a positive direction. Then

Options

A. The amplitude of the block is`(v_(0))/(omega_(0))`
B. The initial phase of the block is `(pi)/(2)`
C. The equation of motion for the block is `(v_(0))/(omega_(0))sinomega_(0)t`
D. The maximum speed of the block is `v_(0)`

Answer

B

Explanation

Initial phase of the block is zero as it is mean position `Rightarrow (1)/(2)mV_(0)^(2)=(1)/(2)kA^(2) Rightarrow A=(V_(0))/(omega_(0))`