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A child swinging on a swing in sitting p...

A child swinging on a swing in sitting position, stands up, then the time period of the swing will.

A

(a)increase

B

(b)decrease

C

(c)remain the same

D

(d)increase if the child is long and decrease if the child is short

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The correct Answer is:
To solve the problem of how the time period of a swing changes when a child standing up, we can follow these steps: ### Step 1: Understand the time period of a pendulum The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where: - \( T \) is the time period, - \( L \) is the length of the pendulum, - \( g \) is the acceleration due to gravity. ### Step 2: Analyze the situation when the child is sitting When the child is sitting on the swing, the effective length \( L \) is the distance from the pivot point (the top of the swing) to the center of mass of the child. ### Step 3: Consider the change when the child stands up When the child stands up, the center of mass of the child rises. This means that the effective length \( L \) of the pendulum decreases. ### Step 4: Relate the change in length to the time period Since \( T \) is proportional to the square root of \( L \), if \( L \) decreases, \( T \) will also decrease. This can be expressed as: - If \( L \) decreases, then \( T \) decreases. ### Step 5: Conclusion Thus, when the child stands up, the time period of the swing will decrease. ### Final Answer The time period of the swing will **decrease** when the child stands up.

To solve the problem of how the time period of a swing changes when a child standing up, we can follow these steps: ### Step 1: Understand the time period of a pendulum The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where: ...
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