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The displacement of a particle varies ac...

The displacement of a particle varies according to the relation `x=4 (cos pit+ sinpit)`. The amplitude of the particle is.

A

-4

B

4

C

`4sqrt(2)`

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
`X=4cospit+sinpit`
Since `cos pi t ` and `sin pi t ` are out of phase by `90^(@)`, amplitude `A=sqrt(4^(2)+4^(2))=4sqrt2`
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