If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then. Which of the following does not change with time ?

Options

A. `a^(2)T+4pi^(2)v^(2)`
B. `aT/x`
C. `aT+2piv`
D. `aT/v`

Answer

B

Explanation

For a simple harmonic motion, acceleration,`a=-omega^(2)x` where `omega` is a constant `omega=(2pi)/T` .
Hence , `a=-4pi^(2)/T^(2) ximplies (aT)/(x)=-(4pi^(2))/T`.
The period of oscillation T is a constant `thereforr(aT)/x` is a constant