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If a spring of stiffness 'k' is cut into...

If a spring of stiffness `'k'` is cut into two parts `'A'` and `'B'` of length `l_(A):l_(B)=2:3`, then the stiffness of spring `'A'` is given by

A

`5/2k`

B

`3k/5`

C

`2k/5`

D

k

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The correct Answer is:
To find the stiffness of spring A after cutting a spring of stiffness \( k \) into two parts A and B with a length ratio of \( l_A : l_B = 2 : 3 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Length Ratio**: Given the ratio \( l_A : l_B = 2 : 3 \), we can express the lengths of parts A and B in terms of a common length. Let the total length of the spring be \( L \). Then: \[ l_A = \frac{2}{5}L \quad \text{and} \quad l_B = \frac{3}{5}L \] 2. **Relationship Between Stiffness and Length**: The stiffness \( k \) of a spring is inversely proportional to its length. This means: \[ k \propto \frac{1}{l} \] Therefore, if we denote the stiffness of spring A as \( k_A \) and the stiffness of spring B as \( k_B \), we can write: \[ k_A \cdot l_A = k \cdot L \] 3. **Express Stiffness of Spring A**: From the relationship above, we can rearrange to find \( k_A \): \[ k_A = \frac{k \cdot L}{l_A} \] 4. **Substituting the Length of Spring A**: Now substitute \( l_A = \frac{2}{5}L \) into the equation: \[ k_A = \frac{k \cdot L}{\frac{2}{5}L} \] 5. **Simplifying the Expression**: The \( L \) cancels out: \[ k_A = \frac{k}{\frac{2}{5}} = k \cdot \frac{5}{2} \] 6. **Final Result**: Thus, the stiffness of spring A is: \[ k_A = \frac{5}{2}k \] ### Conclusion: The stiffness of spring A after cutting the original spring is \( \frac{5}{2}k \).

To find the stiffness of spring A after cutting a spring of stiffness \( k \) into two parts A and B with a length ratio of \( l_A : l_B = 2 : 3 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Length Ratio**: Given the ratio \( l_A : l_B = 2 : 3 \), we can express the lengths of parts A and B in terms of a common length. Let the total length of the spring be \( L \). Then: \[ l_A = \frac{2}{5}L \quad \text{and} \quad l_B = \frac{3}{5}L ...
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