A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of `10^(12)//sec`. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver = 108 and Avagadro number `=6.02xx10^(23)" gm "mole^(-1))

Options

A. `6.4N//m`
B. `7.1N//m`
C. `2.2N//m`
D. `5.5N//m`

Answer

B

Explanation

For a harmonic oscillator, `T=2pisqrt(m/k)`
Where, k = force constant and `T=1/f`
`therefore k=4pi^(2)f^(2)m`
`4xx(22/7)^(2)xx(10^(22))^(2)xx(108xx10^(-3))/(6.02xx10^(23)) implies k=7.1N//m`