A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :

Options

A. `A/sqrt(2)`
B. `A/2sqrt(2)`
C. A
D. `A/2`

Answer

A

Explanation

KE=PE
`1/2mV^(2)=1/2kx^(2)`
`1/2momega^(2)(A^(2)-X^(2))=1/2momega^(2)x^(2)`
`A^(2)-X^(2)=X^(2), x=A/sqrt(2)`