A particle executes S.H.M. between `x = -A` and `x = + A`. The time taken for it to go from 0 to A/2 is `T_(1)` and to go from A/2 to A is `T_(2)`. Then

Options

A. `T_(1)ltT_(2)`
B. `T_(1)gtT_(2)`
C. `T_(1)=T_(2)`
D. `T_(1)lt2T_(2)`

Answer

A

Explanation

The velocity of a body executing SHM is maximum at its centre and decreases as the body proceeds to the extremes. Therefore, if the time taken for the body to go from O to `A//2` is `T_(1)` and to go from A//2 to A is `T_(2)`, then obviously `T_(1)ltT_(2)`