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A particle executes S.H.M. between x = -...

A particle executes S.H.M. between `x = -A` and `x = + A`. The time taken for it to go from 0 to A/2 is `T_(1)` and to go from A/2 to A is `T_(2)`. Then

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The correct Answer is:
2
From `x=A sin omega t` , we have
`(A)/(2)=Asinomegat_(1)implies omegat_(1)=(pi)/(6)` ...(i)
Also `A=Asinomega(t_(1)+t_(2))`
`omega(t_(1)+t_(2))` ...(ii)
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