The amplitude of a wave disturbance propagating along positive X-axis is given by `y=1/(1+x^(2))` at t=0 and `y=1/[1+(x-2)^(2)]` at t=4 s where x and y are in metre. The shape of wave disturbance does not change with time. The velocity of the wave is

Answer

`0.5`

Explanation

Wave is `f(vt-x)=(1)/(1+(vt-x)^(2)), v^(2) implies v=1/2m//s ` (yowards+x)
The negative sign indicates that wave is travelling towards left.