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In a U-tube, two immiscible liquids of d...

In a U-tube, two immiscible liquids of density ` rho _ 1 and rho _ 2 ` are arranged as shown in figure. The right part of the tube is closed at the top and some air is entrapped above liquid of density ` rho _2 `. The gauge pressure of this air is :

A

Zero

B

` (rho_2 - rho_1 ) gh `

C

` (rho_1 - rho_2) gh`

D

Not possible

Text Solution

Verified by Experts

The correct Answer is:
C
The pressure of entrapped air with respect to atmospheric pressure is called the gauge pressure. Writing pressure relation starting from the open end, we get ` P _ 0 + rho _ 1 gh - rho _ 2 gh = P_(air) `
Therefore `, P_(air ) - P _ 0 = (rho _1 - rho _2 ) gh` (gauge)
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