Figure shows a liquid flowing through a tube at the rate of `0.1 m^(3)//s`. The tube is branched into two semicircular tubes of cross-sectional area `A//3` and `2A//3`. The velocity of liquid at `Q` is (the cross section of the main tube is `A =10^(-2) m^(2)` and `v_(p) = 20 m//s`)

Options

A. 5 m/s
B. 30 m/s
C. 35 m/s
D. None of these

Answer

A

Explanation

Using equation of continuity. Rate = `r=(A)/(3)V_(p)+(A-(A)/(3))V_(Q)`
`RightarrowV_(P)+2V_(Q)=(3r)/(A)=(3xx0.1)/(10^(-2))=30m//s," ""As"V_(P)=20m//sRightarrowV_(Q)=5m//s`