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Two capillary tubes of the same length b...

Two capillary tubes of the same length but different radii `r_(1) " and " r_(2)` are fitted in parallel to the bottom of a vessel. The pressure head is `rho`. What should be the radius of a single tube that can replace the can replace the two tubes so that the rate of flow is same as before

A

` (17) ^(1//4) r `

B

` 17 r `

C

` 8.5 r `

D

` sqrt(17) r `

Text Solution

Verified by Experts

The correct Answer is:
A
Radius R of the single tube is given by
`(pipR^4)/(8eta1)=(pipr^4)/(8eta1)+(pip(2r)^4)/(8eta1)" "or" "R^(4)=r^(4)+16r^(4)" "or" "R=(17)^(1//4)r` which is choice (A).
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