The spring balance A reads `2 kg` with a block in suspended from it. A balance `B` reads `5 kg` when a beaker with liquid is put on the pan of the balance. The two balances are now so arranged that the hinging mass is inside the liquid in the beaker as shown in the figure. In this situation,

Options

A. The balance A will read more than 2 kg
B. The balance B will read more than 5 kg
C. The balance A will read less than 2 kg and B will read more than 5 kg
D. The balance A and B will read 2 kg and 5 kg, respectively

Answer

B, C

Explanation

When the block of mass m is arranged as shown in the figure, an upthrust `F_(Y)` will act will act on the mass which will decrease the reading on A. But according to Newton’s third law, to each and every action, there is equal and opposite reaction, So `F_(Y)` will act on the liquid of the breaker which will increase the reading in B.