A person in a lift is holding a water jar, which has a small hole at the lower end its side. When the lift is at rest, the water jet coming out of the hole hits the floor of the lift at a distance d of 1.2 m from the person. In the following, state of the lift’s motion is given in Column I and the distance where the water jet hits the floor of the lift is given in Column II. Match the statements from list I with those in list II and select the correct answer using the code given below the lists.

Options

A. A-Q, B-R, C-Q, D-S
B. A-Q, B-R, C-P, D-S
C. A-P, B-P, C-P, D-S
D. A-Q, B-R, C-P, D-P

Answer

C

Explanation

When lift is moving up with acceleration a, speed of water from jar is given by ` v = sqrt(2g_("effective")h ) `
Where ` g_("effective") = (g + a ) `
Hence ` v = sqrt(2 (g+a ) h) " " `…(i)
Time taken by water to reach the base of the lift is given by
` H = (1)/(2) (g +a )t ^ 2 rArr t = sqrt ((2H )/((g + a)) ) " " ...(ii) `
Horizontal distance covered by water on the floor of the lift.
` d = vt = sqrt (2 (g + a ) h) xx sqrt((2H)/( (g + a)) ) = sqrt (4 H h ) `
So d is independent of acceleration of the lift. ` therefore A, B, C- p`
(S) When lift falls freely, effective acceleration of the person in the lift holding the jar is zero, so no water leaks out of the jar ` (v = sqrt (2 (g- g ) h ) = 0 ) `
D- s
So, A- p, B-p, C-p , D- s