A flask of mercury is sealed off at `20^@C` and is completely filled with mercury. If the bulk modulus for mercury is 250 Mpa and the coefficient of volume expansion of mercury is `1.82xx10^(-4)//^(@)C` and the expansion of glass is ignored, the pressure of mercury within flask at `100^@C` will be

Options

A. 10 MPa
B. 7.2 MPa
C. 3.6 MPa
D. 2.4 MPa

Answer

C

Explanation

If V is initial volume then, The natural volume at `T=100^(@)C` will be
`V(l+YDeltaT)`
So , `DeltaV=-VYDeltaT`
Also `beta=-V(DeltaP)/(DeltaV)=-V(DeltaP)/(-VYDeltaT)=(DeltaP)/(YDeltaT)or,DeltaP=250xx1.82xx10^(-4)xx80,P_(2)=3.6Mpa`