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A wall is made of equally thick layers A and B of different matierals. Thermal conduvtivity of A is twice that of B. In the stedy state, the temperature difference across the wall is `36^(@)C` . The temperature difference across the layer A is

A

`6^(@)C`

B

`12^(@)C`

C

`18^(@)C`

D

`24^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`H=(2k(T_(1)-T))/(L)=(kA(T-T_(2)))/(L)rArr2T_(1)-3T=-T_(2)`
Adding `T_(1)` on both sides:
`3T_(1)-3T=T_(1)-T_(2)rArrT_(1)-T=(T_(1)-T_(2))/(3)=(36)/(3)=12^(@)C`
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