Some steam at `100^(@)C` is passed into `1.1` kg of water constained in a calorimeter of water equivalent 20 gm at `15^(@)C` so that the temperature of the calorimeter and its contained rises to `80^(@)C` What is the mass of steam condensing (in kg).

Options

A. `0.130`
B. `0.065`
C. `0.260`
D. `0.135`

Answer

A

Explanation

Heat required, `Q=(1.1+0.02)xx10^(3)xx1xx(80-15)=72800cal`
Let m gram of steam is condensed. Then heat loss `=mxx540+mxx1xx20=560m`
Heat loss = heat gain
`rArr560m=72800 " " rArrm=130g=0.130kg`