What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realise from your answer why ordinary capacitors are in the range of `mu F` or less. However, electrolytic capacitors do have a much larger capacitance (0.1 F) because of very minute separation between the conductors.]

Explanation

Capacitance of parallel plate capacitor `C=(epsi_(0)A)/(d)` , Area `A=(Cd)/(epsi_(0))=(2xx(0.5xx10^(-2)))/(8.85xx10^(-12))=1.13xx10^(9)m^(2)`
this is too large. That is why ordinary capacitors are in the range of `muF` or even less, however, in electrolytic capacitors the separation (d) is very small, so they have capacitances of the order of 0.1F.