Two identical metal plates are given positive charges `Q_1 and Q_2`(ltQ_1),` respectively. If they are brought close together to form a parallel to form a parallel plate capacitor with capacitance C, the potential difference between them will be

Options

A. `(Q_(1)+Q_(2))/(2C)`
B. `(Q_(1)+Q_(2))/(C)`
C. `(Q_(1)-Q_(2))/(C)`
D. `(Q_(1)-Q_(2))/(2C)`

Answer

D

Explanation

Resultant field `=(Q_(1)-Q_(2))/(2in_(0)A),V=((Q_(1)-Q_(2))/(2in_(0)A))d=(Q_(1)-Q_(2))/(2C)`