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A parallel plate capacitor with air as t...

A parallel plate capacitor with air as the dielectric has capacitance C. A slab of dielectric constant K and having the same thickness as the separation between plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be :

A

`(K+3)(C)/(4)`

B

`(K+2)(C)/(4)`

C

`(K+1)(C)/(4)`

D

`(KC)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_("net")=(3in_(0)A)/(4d)+(in_(0)AK)/(4d)`.
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