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A capacitor of capacitance value 1 muF i...

A capacitor of capacitance value `1 muF` is charged to 30 V and the battery is then disconnected. If it is connected across a `2 muF` capacotor, then the energy lost by the system is

A

`300muF`

B

`450muF`

C

`225muF`

D

`150muF`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(1)=(1)/(2)C_(1)V_(1)^(2)=450xx10^(-6)J`
common potential `V=(q_(1)+q_(2))/(sigma_(1)+sigma_(2))=10`volt, `E_(2)=(1)/(2)(C_(1)+C_(2))V^(2)=150xx10^(-6)J`
Loss=`(450-150)muJ=300muJ`
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