A parallel plate capacitor has two layers of dielectrics as shown in figure. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is

Answer

6

Explanation

Let the electric field in dielectrics be `E_(1) and E_(2)`
Then, `(E_(1))/(E_(2))=(K_(2))/(K_(1))=12`
Let the potntial difference across the two dielectric layers be `DeltaV_(1) and DeltaV_(2)`
then, `(DeltaV_(1))/(DeltaV_(2))=(E_(1)d)/(E_(2)2d)=(12)/(2)=6`.