The equivalent capacitance between A and B will be

Answer

9

Explanation

You can label each junction in this circuit, and then redraw it. It will become clear that the first three capacitor are all in parallel with each other, and the next two capacitors are shorted, so they play no role in the circuit.
So, `(1)/(C_(eff))=(1)/(3C)+(1)/(C) implies C_(eff)=(3C)/(4)=(3)/(4) xx12=9muF`.