Figure shows a network of a capacitor and resistors. Find the charge on capacitor in steady state in `muC`.

Answer

16

Explanation

Let the potential of the junction be V. then, by applying KCL at the junction,
`(6-V)/(2)+(4-V)/(4)+(8-V)/4 =0, 12-2V+4-V+8-V=0`
`24=4V, V=6` volt
Potential drop across capacitor, `=6-(-10),=16V,` Charge on capacitor=16`muC`.