Home
Class 12
PHYSICS
Seven capacitors, each of capacitance 2 ...

Seven capacitors, each of capacitance `2 muF`, are to be combined to obtain a capacitance `10//11 muF`. Which of the following combinations is possible?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A

In series,`c=(c_1c_2)/(c_1+c_2)`
`therefore ^(c)"net"=((10)(1))/(10+1)=10/11muF`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CAPACITORS

    VMC MODULES ENGLISH|Exercise JEE Advance ( Archive ) LEVEL 3|1 Videos
  • CAPACITORS

    VMC MODULES ENGLISH|Exercise JEE Advance ( Archive ) LEVEL 4|1 Videos
  • CAPACITORS

    VMC MODULES ENGLISH|Exercise JEE Main (Archive) LEVEL-1|36 Videos
  • BASIC MATHEMATICS & VECTORS

    VMC MODULES ENGLISH|Exercise Impeccable|50 Videos
  • CURRENT ELECTRICITY

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-F|10 Videos

Similar Questions

Explore conceptually related problems

Seven capacitors each of capacitance 2muF are to be connected in a configuration to obtain an effective capacitance of (10/11)muF . Which of the combination (s) shown in figure will achieve the desired result?

Seven capacitors, each a of a cpacitance 2muF , are to be connected in a configuration to obatin an effective capacitance of ((16)/(13))muF . Which of the combinations, shown in figure below, will achieve the desired value ?

Knowledge Check

  • Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

    A
    connecting them in series
    B
    connecting them is parallel
    C
    connecting two in series and one in parallel
    D
    connecting two in parallel and one is series
  • Similar Questions

    Explore conceptually related problems

    Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

    Three capacitors each of capacity 4 muF are to be connected in such a way that the effective capacitance is 6 muF . This can be done by

    Three capacitors each of capacitance 9 pF are connected in series. (a) What is the total capacitance of the combination ? (b) What is the potential difference across each capacitor if the combination is connected to a 120V supply.

    Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

    Six identical capacitors each of capacitance 2 muF are connected as shown below. The equivalent capacitance between the points A and B is

    The minimum number of condensers each capacitance of 2 muF , in order to obtain result capacitance of 5 muF will be

    Three capacitors of capacitance 3 muF are connected in a circuit. Then, their maximum and minimum capacitance will be