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In the circuit shown in the figure, the...

In the circuit shown in the figure, there are two prallel plate capacitors each of capacitance C. The switch `S_1` is pressed first to fully charge the capacitor `C_1` and then released. The switch S is then pressed to charge the capacitor `C_2`. After some time, `S_2` is released and then S is pressed. After some time,

A

The charge on the upper plate of `C_(1) is 2CV_(0)`

B

The charge on the upper plate of `C_(1) is CV_(0)`

C

The charge on the upper plate of `C_(2) is 0`

D

The charge on the upper plate of `C_(2) is -CV_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B, D
After pressing `S_1` chare on upper plate `c_1` is `cv_0`.After pressing `S_2` this charge equally distributes in two capicators. Therefore charge on upper plates of both capacitor will be `+CV_0`. When `S_2` is released and `S_2`pressed,charge on upper plate of `c_1` remains unchanged `(=+cv_0)` but charge on upper plate of is according to new battery `(=-cv_0)`
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