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A 3.0 cm wire carrying a current of 10 A...

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Text Solution

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Length of the wire `1=3cm=0.03m,, ` Current flowing in the wire `1-10A`
Magnetic field `B=0.27T`
Angle between the current and magnetic field,`theta=90^(@)` (Because magnetic field produced by a solenoid is along its axis and current carrying wire is kept perpendicular to the axis)
`F=B i l sin theta, =0.27xx10xx0.03sin 90^(@), =8.1xx10^(-2)N`
Hence, the magnetic force on the wire is `8.1xx10^(-2)N`. The direction of the force can be obtained from Fleming’s left hand rule
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Knowledge Check

  • An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire is

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