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A straight wire carries a current of 10A...

A straight wire carries a current of 10A. An electron moving at `10^(3)` m/s is at distance 2.0 cm from the wire. Find the force acting on the electron if its velocity is directed toward the wire?

Text Solution

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Here I=10A , `V=10^(3)//s` , `R=2.0 cm =2xx10^(-2)m`
Force acting on moving electron (F)`=qvB sin theta impliesB=(mu_(0))/(4pi)(2I)/r`
`B=(10^(-7)xx2xx10)/(2xx10^(-2))=10^(-4)` Tesla and `_|_` to the plane of paper and directed downwards.
Now `F=1.6xx10^(-19)xx10^(3)xx10^(-4)sin 90^(@)`
`F=1.6xx10^(-20)` Newton.
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