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Currents through ABC and A^'B^'C^' is I,...

Currents through ABC and `A^'B^'C^'` is I, figure. What is the magnetic field at P? `BP=PB^'=r`. (Here `C^'B^'PBC` are collinear)

A

`B=1/(4pi)(2I)/r`

B

`B=(mu_(0))/(4pi)((2I)/r)`

C

`B=(mu_(0))/(4pi)(I/r)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`B_(P)=2xx(mu_(I))/(4pir)=(mu_(0)i)/(2pir)`
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