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A square loop of side a carris a current...

A square loop of side a carris a current `I`. The magnetic field at the centre of the loop is

A

`(2mu_(0)Isqrt(2))/(pia)`

B

`(mu_(0)Isqrt(2))/(pia)`

C

`(4mu_(0)Isqrt(2))/(pia)`

D

`(mu_(0)I)/(pia)`

Text Solution

Verified by Experts

The correct Answer is:
A
`B_(C)=4[(mu_(0))/(4pi)I/(a//2)(sin 45^(@)+sin 45^(@))]=(2sqrt(2)mu_(0)I)/(pia)`
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