A current carrying conductor placed in a magnetic field experiences maximum force when angle between current and magnetic field is :

Options

A. (a)`3pi//4`
B. (b)`pi//2`
C. (c)`pi//4`
D. (d)Zero

Explanation

To solve the question regarding the angle between the current and the magnetic field at which a current-carrying conductor experiences maximum force, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Force on a Conductor**:
The force \( F \) experienced by a current-carrying conductor in a magnetic field is given by the formula:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]
where:
- \( F \) = force on the conductor
- \( I \) = current flowing through the conductor
- \( L \) = length of the conductor in the magnetic field
- \( B \) = magnetic field strength
- \( \theta \) = angle between the direction of current and the magnetic field

2. **Identifying Maximum Force Condition**:
To find the angle at which the force is maximum, we need to maximize the sine function, \( \sin(\theta) \). The sine function reaches its maximum value of 1 when:
\[ \sin(\theta) = 1 \]

3. **Finding the Angle**:
The sine function equals 1 at:
\[ \theta = 90^\circ \quad \text{or} \quad \theta = \frac{\pi}{2} \text{ radians} \]

4. **Conclusion**:
Therefore, the angle between the current and the magnetic field at which the current-carrying conductor experiences maximum force is:
\[ \theta = 90^\circ \quad \text{or} \quad \frac{\pi}{2} \text{ radians} \]

5. **Checking Options**:
If provided with options, we can check which option corresponds to \( 90^\circ \) or \( \frac{\pi}{2} \) radians.

### Final Answer:
The angle between the current and the magnetic field at which the current-carrying conductor experiences maximum force is \( 90^\circ \) or \( \frac{\pi}{2} \) radians.

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