Home
Class 12
PHYSICS
Consider the magnetic field produced by ...

Consider the magnetic field produced by a finitely long current carrying wire .

A

(a)The lines of field will be concentric circles with centre on the wire.

B

(b)There can be two points in the same plane where magnitude of magnetic field is same.

C

(c)There can be large number of points where magnitude of the magnetic field is same.

D

(d)The magnetic field at a point is inversely proportional to the distance of the point from the wire.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the magnetic field produced by a finitely long current-carrying wire, we will analyze the magnetic field characteristics and evaluate the given statements. ### Step-by-Step Solution: 1. **Understanding the Magnetic Field Due to a Current-Carrying Wire**: - When a current flows through a wire, it generates a magnetic field around it. For an infinitely long straight wire, the magnetic field lines are concentric circles centered around the wire. **Hint**: Recall the right-hand rule to determine the direction of the magnetic field around a current-carrying wire. 2. **Formula for Magnetic Field**: - The magnetic field (B) at a distance (r) from a long straight wire carrying a current (I) is given by the formula: \[ B = \frac{\mu_0 I}{2 \pi r} \] - Here, \(\mu_0\) is the permeability of free space. **Hint**: Remember that the magnetic field strength decreases as the distance from the wire increases. 3. **Analyzing the Statements**: - **Statement A**: The lines of the magnetic field will be concentric circles with the center on the wire. - This statement is **correct** because the magnetic field lines around a straight wire are indeed concentric circles. - **Statement B**: There can be two points in the same place where the magnetic field is the same. - This statement is also **correct**. Due to the nature of the magnetic field, multiple points can have the same magnetic field strength at different distances from the wire. - **Statement C**: There can be a large number of points where the magnitude of the field is the same as they are long wire produced by the magnetic field. - This statement is **correct** as well. The magnetic field strength can be the same at various points around the wire. - **Statement D**: The magnetic field at a point is inversely proportional to the distance of the point from the wire. - This statement is **incorrect**. The magnetic field is inversely proportional to the distance (r), but not simply to r; it is proportional to \( \frac{1}{r} \), not \( \frac{1}{r^2} \). **Hint**: Compare the nature of the magnetic field with respect to distance and remember the specific formula. 4. **Conclusion**: - The correct statements are A, B, and C. Statement D is incorrect because the relationship is not as stated. ### Final Answer: - Statements A, B, and C are correct. Statement D is incorrect.

To solve the question regarding the magnetic field produced by a finitely long current-carrying wire, we will analyze the magnetic field characteristics and evaluate the given statements. ### Step-by-Step Solution: 1. **Understanding the Magnetic Field Due to a Current-Carrying Wire**: - When a current flows through a wire, it generates a magnetic field around it. For an infinitely long straight wire, the magnetic field lines are concentric circles centered around the wire. **Hint**: Recall the right-hand rule to determine the direction of the magnetic field around a current-carrying wire. ...
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECTS OF CURRENT

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|75 Videos
  • MAGNETIC EFFECTS OF CURRENT

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|78 Videos
  • MAGNETIC EFFECTS OF CURRENT

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos
  • LIQUIDS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (LEVEL -2)|55 Videos
  • MOCK TEST 1

    VMC MODULES ENGLISH|Exercise PART I : PHYSICS (SECTION-2)|10 Videos
VMC MODULES ENGLISH-MAGNETIC EFFECTS OF CURRENT -LEVEL 2
  1. Find the magnetic field at P due to the arrangement show in figure

    Text Solution

    |

  2. Two long mutually perpendicular conductors carrying currents I1 and I2...

    Text Solution

    |

  3. Consider the magnetic field produced by a finitely long current carryi...

    Text Solution

    |

  4. Two long thin, parallel conductors carrying equal currents in the same...

    Text Solution

    |

  5. According to Biot-Savarat's law, magentic field due to a straight curr...

    Text Solution

    |

  6. According to Biot-Savart’s law, magnetic field due to a straight curre...

    Text Solution

    |

  7. Match the statements given in Column I with the oxidation states given...

    Text Solution

    |

  8. A current I is flowing in a straight conductor of length L. The magnet...

    Text Solution

    |

  9. Three rings, each having radius R, are placed mutually perpendicular t...

    Text Solution

    |

  10. A current carrying conductor is in the form of a sine curve as shown, ...

    Text Solution

    |

  11. A long thin walled pipe of radius R carries a current I along its leng...

    Text Solution

    |

  12. The figure shows the cross section of two long coaxial tubes carrying ...

    Text Solution

    |

  13. Two long conductors are arranged as shown above to form overlapping cy...

    Text Solution

    |

  14. The protein cost called capsied made of small subunits called capsomer...

    Text Solution

    |

  15. In Fig. the circular and the straight parts of the wire are made of sa...

    Text Solution

    |

  16. A long, straight wire of radius R carries a current distributed unifor...

    Text Solution

    |

  17. A current carrying conductor is in the form of a sine curve as shown, ...

    Text Solution

    |

  18. Statement 1: If we consider two wires carrying current l(1) and l(2), ...

    Text Solution

    |

  19. An electron moving with a velocity oversetrarrV(1) = 2hatim//s at a po...

    Text Solution

    |

  20. A charged particle moves with velocity vec v = a hat i + d hat j in a ...

    Text Solution

    |