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A charged particle moves with velocity v...

A charged particle moves with velocity `vec v = a hat i + d hat j` in a magnetic field `vec B = A hat i + D hat j.` The force acting on the particle has magnitude F. Then,

A

(a)F = 0, if aD = dA

B

(b)F = 0, if aD = – dA

C

(c)F = 0, if aA = – dD

D

(d)`F prop (a^(2)+d^(2))^(1//2)xx(A^(2)+D^(2))^(1//2)`

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To solve the problem, we need to find the relationship between the force acting on a charged particle moving in a magnetic field, given its velocity and the magnetic field vectors. ### Step-by-Step Solution: 1. **Identify the Given Vectors**: - The velocity vector of the charged particle is given as: \[ \vec{v} = a \hat{i} + d \hat{j} \] - The magnetic field vector is given as: \[ \vec{B} = A \hat{i} + D \hat{j} \] 2. **Use the Formula for Magnetic Force**: - The force \(\vec{F}\) acting on a charged particle moving in a magnetic field is given by the equation: \[ \vec{F} = q (\vec{v} \times \vec{B}) \] - Here, \(q\) is the charge of the particle. 3. **Calculate the Cross Product \(\vec{v} \times \vec{B}\)**: - To find the cross product, we can use the determinant form: \[ \vec{v} \times \vec{B} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ a & d & 0 \\ A & D & 0 \end{vmatrix} \] - Expanding the determinant, we get: \[ \vec{v} \times \vec{B} = \hat{i}(d \cdot 0 - 0 \cdot D) - \hat{j}(a \cdot 0 - 0 \cdot A) + \hat{k}(aD - dA) \] - This simplifies to: \[ \vec{v} \times \vec{B} = (aD - dA) \hat{k} \] 4. **Substitute Back into the Force Equation**: - Now substituting the cross product back into the force equation: \[ \vec{F} = q (aD - dA) \hat{k} \] 5. **Determine the Magnitude of the Force**: - The magnitude of the force is given by: \[ F = |q| |aD - dA| \] - Thus, the force acting on the particle has a magnitude \(F\) which is proportional to the absolute value of the expression \(aD - dA\). 6. **Condition for Zero Force**: - The force will be zero when: \[ aD - dA = 0 \quad \Rightarrow \quad aD = dA \] - This implies that the force acting on the particle is zero under this condition. ### Final Relation: The relationship between the charge, velocity, magnetic field, and force can be summarized as: \[ F = |q| |aD - dA| \] The force is zero when \(aD = dA\).

To solve the problem, we need to find the relationship between the force acting on a charged particle moving in a magnetic field, given its velocity and the magnetic field vectors. ### Step-by-Step Solution: 1. **Identify the Given Vectors**: - The velocity vector of the charged particle is given as: \[ \vec{v} = a \hat{i} + d \hat{j} ...
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