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A conducting rod of mass m and length ...

A conducting rod of mass m and length l is placed over a smooth horizontal surface . A unifrom magnetic field B is acting perpendicular to the rod. Charge q is suddenly passed throught the red it accquire an initnal velocity on the surface , then q is equal to

A

`(2mv)/(Bl)`

B

`(Bl)/(2mv)`

C

`(mv)/(Bl)`

D

`(Blv)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
C
Using, impulse = change in linear momentum, we have
`intF dt=mv` or `int(iBl)dt=mv` or `Blq=mv` (as `intidt=q):.q=(mv)/B`
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