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In a region, steady and uniform electric...

In a region, steady and uniform electric and magnetic fields are present . These two fields are parallel to each other. A charged particle is released from rest in this region . The path of the particle will be a

A

Helix

B

Straight line

C

Ellipse

D

Circle

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The correct Answer is:
To solve the problem, we need to analyze the motion of a charged particle in the presence of both electric and magnetic fields that are parallel to each other. ### Step-by-Step Solution: 1. **Understanding the Fields**: - We have a uniform electric field (E) and a uniform magnetic field (B) that are parallel to each other in a given region. - Let's denote the electric field direction as positive along the x-axis. 2. **Charged Particle Released from Rest**: - A charged particle (let's assume it has a positive charge +Q) is released from rest in this region. - Since it starts from rest, its initial velocity (V) is 0. 3. **Force due to Electric Field**: - The force acting on the charged particle due to the electric field is given by: \[ F_E = Q \cdot E \] - This force will act in the direction of the electric field (along the x-axis). 4. **Force due to Magnetic Field**: - The force acting on the charged particle due to the magnetic field is given by the Lorentz force equation: \[ F_B = Q \cdot (V \times B) \] - Since the particle starts from rest, its initial velocity \( V = 0 \). Therefore, the magnetic force at the moment of release is: \[ F_B = Q \cdot 0 \cdot B = 0 \] - This means that initially, the magnetic field does not exert any force on the particle. 5. **Resultant Force**: - Since the only force acting on the particle at the moment of release is the electric force \( F_E \), the particle will start to accelerate in the direction of the electric field. 6. **Path of the Particle**: - As the particle accelerates due to the electric field, it will continue to move in a straight line along the direction of the electric field. - The magnetic field does not influence the path at the moment of release because the velocity is zero and the forces are parallel. ### Conclusion: The path of the charged particle will be a straight line in the direction of the electric field.

To solve the problem, we need to analyze the motion of a charged particle in the presence of both electric and magnetic fields that are parallel to each other. ### Step-by-Step Solution: 1. **Understanding the Fields**: - We have a uniform electric field (E) and a uniform magnetic field (B) that are parallel to each other in a given region. - Let's denote the electric field direction as positive along the x-axis. ...
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