The region between y =0 and y=d constains a magnetic field `vecB = Bvecz`. A particle of mass m and charge q enters of the region with a velocity `vecv = v veci`. If `d =(mv)/(2qB)` the acceleration of the charged particle at the point of its emergence at the other side is :

Options

A. `(qvB)/m((sqrt(3))/2 hati +1/2 hatj)`
B. `(qvB)/m(1/2 hat (sqrt(3))/2hatj)`
C. `(qvB)/m((hati+hatj)/(sqrt(2)))`
D. `(qvB)/m((-hatj+hati)/(sqrt(2)))`

Answer

D

Explanation

Assuming charge particle is at origin initially,
`vecv=vhati`
then charge particle will go grazingly to magnetic field.
Hence none of options will be answer.