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Find the magnetic field at point P due t...

Find the magnetic field at point `P` due to a straight line segment `AB` of length `6 cm` carrying a current of `5A`. (See figure)
`(mu_(0) = 4 pi xx 10^(-7) N-A^(-2))`.
.

A

`3.0xx10^(-5)T`

B

`2.5xx10^(-5)T`

C

`2.0xx10^(-5)T`

D

`1.5xx10^(-5)T`

Text Solution

Verified by Experts

The correct Answer is:
D
`B=(mu_(0)I)/(4pir)(sin alpha+sinbeta)`
`r=4cm`
`sin alpha=sin beta=3//5impliesbeta=1.5xx10^(-5)T`
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