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Two particles A and B of masses mA and m...

Two particles `A` and `B` of masses `m_A` and `m_B` respectively and having the same charge are moving ina plane. A uniform magnetic field exists perependicular to this plane. The speeds of the particles are `v_A` and `v_B` respectively and the trajectories are as shown in the figure. Then,

A

`m_(A)v_(A)ltm_(B)v_(B)`

B

`m_(A)v_(A) gt m_(B)v_(B)`

C

`m_(A)ltm_(B)` and `v_(A)ltv_(B)`

D

`m_(A)=m_(B)` and `v_(A)=v_(B)`

Text Solution

Verified by Experts

The correct Answer is:
B

Radius of the circle `=(mv)/(Bq)` or radius `prop mv` if B and q are same `("Radius")_(A)gt("Radius")_(B):.m_(A)v_(A)gtm(B)v_B)`
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