In the figure shown a charge q moving w...

In the figure shown a charge `q` moving with a velocity v along the x-axis enter into a region of uniform magnetic field. The minimum value `v` so that the charge `q` is able to enter the region `xgtb`

`(dbB)/m`

`(q(b-a)B)/m`

`(qaB)/m`

`(q(b+a)B)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:

If `(b-a)ger` (r= radius of circular path of particle)
The particle cannot enter the regioin `x gtb`. So the enter in the region `x gtb`
`rgt(b-a)` or `(mv)/(Bq)gt(b-a)` or `vgt(q(b-q)B)/m`

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