`H^(+), He^(+)` and `O^(2+)` ions having same kinetic energy pass through a region of space filled with uniform magnetic field B directed perpendicular to the velocity of ions. The masses of the ions
`H^(+), He^(+)` and `O^(2+)` are respectively, in the ratio `1:4:16`. As a result

Options

A. `H^(+)` will be deflected most
B. `O^(2+)` will be deflected most
C. `He^(+)` and `O^(2+)` will be deflected equally
D. All will be deflected equally

Answer

A, C

Explanation

`r=(mv)/(Bq)=p/(Bq)=(sqrt(2Km))/(Bq)` i.e. `r prop (sqrt(m))/q`

If K and B are same i.e. `r_(H)=:r_(He)+:r_(O^(2+))=(sqrt(1))/1:(sqrt(4))/1=(sqrt(16))/2=1:2:2`
Therefore `He^(+)` and `O^(2+)` will be deflected equally but `H^(+)` having the least radius will be deflected most.