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(sum(r=0)^(10) ""^(10)C(r) ) (sum(r=0)^(...

`(sum_(r=0)^(10) ""^(10)C_(r) ) (sum_(r=0)^(10)(-1)^(m) (""^(10)C_(m))/(2^(m)))` is equal to

A

`2^(10)`

B

`2^(20)`

C

1

D

`5^(n)-1`

Text Solution

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The correct Answer is:
C
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VMC MODULES ENGLISH-BINOMIAL THEOREM-LEVEL 1
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